Question

In the adjoining figure, P and Q are two points on equal sides AB
and AC of an isosceles triangle ABC such that AP = AQ.
Prove that BQ = CP​

Answer 1

Answer:

Step-by-step explanation:

In ΔBAQ and ΔCAP

BA=CA

angleA=angleA

AQ=AP

ΔBAQ congruent with ΔCAP(SAS)

BQ=CP(CPCT)