Math, asked by akshita27, 1 year ago

In the adjoining figure, P and Q are two points on equal sides AB and AC of an isosceles triangle ABC such that AP = AQ. Prove that BQ =CP .

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Answers

Answered by ARVIND0407
80
this is the answer of this question ..
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akshita27: thanks for the answer..
Answered by amirgraveiens
38

BQ =CP

Proved Beloiw.

Step-by-step explanation:

Given:

As shown in the figure, P and Q are two points on equal sides AB and AC of an isosceles triangle ABC.

Therefore, AB = AC and AP = AQ.

Thus AB - AP = AC - AQ.

Hence BP = CQ.

Now in triangles BCP and BCQ,

BP = CQ                   [given]

angle B = angle C   [ABC is an isosceles triangle]

and BC is common.

Hence triangles BCP and BCQ are congruent (two and the included angle of one triangle are equal to that of the other).

Therefore BQ = CP which are opposite the equal angles B and C.

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