In the adjoining figure, P and Q are two points on equal sides AB and AC of an isosceles triangle ABC such that AP = AQ. Prove that BQ =CP .
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BQ =CP
Proved Beloiw.
Step-by-step explanation:
Given:
As shown in the figure, P and Q are two points on equal sides AB and AC of an isosceles triangle ABC.
Therefore, AB = AC and AP = AQ.
Thus AB - AP = AC - AQ.
Hence BP = CQ.
Now in triangles BCP and BCQ,
BP = CQ [given]
angle B = angle C [ABC is an isosceles triangle]
and BC is common.
Hence triangles BCP and BCQ are congruent (two and the included angle of one triangle are equal to that of the other).
Therefore BQ = CP which are opposite the equal angles B and C.
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