In the adjoining figure, P is a point in the interior of angle AOB. if PL perdicular OA and PM perdicular OB such that PL=PM,show that OP is the bisector of angle AOB.
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In the above Question , the following information is given -
In the adjoining figure, P is a point in the interior of angle AOB.
PL is perpendicular OA and PM is perpendicular OB such that PL= PM .
To show -
OP is the bisector of angle AOB.
Solution -
We can say that OP is the bisector of angle AOB if and only if triangle OPL is congruent to triangle OPM .
So , we need to prove that triangle OPL is congruent to triangle OPM .
Now , -
PL is perpendicular OA and PM is perpendicular OB such that PL= PM .
So ,
Angle OLP = Angle OMP ......... { 1 }
PL = PM .......... {2}
OP = OP ......... { 3 }
So , triangle OLP is congruent to triangle OMP by R. H. S congruency .
So ,
Angle LOP = Angle POM { Corresponding parts of congruent triangles }
So , we can say that -
OP is the bisector of angle AOB.
Hence Shown .....
_______________________________________________________
In the adjoining figure, P is a point in the interior of angle AOB.
PL is perpendicular OA and PM is perpendicular OB such that PL= PM .
To show -
OP is the bisector of angle AOB.
Solution -
We can say that OP is the bisector of angle AOB if and only if triangle OPL is congruent to triangle OPM .
So , we need to prove that triangle OPL is congruent to triangle OPM .
Now , -
PL is perpendicular OA and PM is perpendicular OB such that PL= PM .
So ,
Angle OLP = Angle OMP ......... { 1 }
PL = PM .......... {2}
OP = OP ......... { 3 }
So , triangle OLP is congruent to triangle OMP by R. H. S congruency .
So ,
Angle LOP = Angle POM { Corresponding parts of congruent triangles }
So , we can say that -
OP is the bisector of angle AOB.
Hence Shown .....
_______________________________________________________
Answered by
7
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