Question

in the adjoining figure , p is a point in the interior of angle AOB. PM perpendicular OB and PN perpendicular OA . if angle NOM = 60 degree , what is the measure of angle NPM?​

Answer 1

Answer:

as we know that total sum of all angles of a quadrilateral is 360°

so here we can say that

angle NOM+NPM+PMO+ONP=360

therefore on substituting vales we get

60+NPM+90+90=360

so NPM=120°

Answer 2

Answer:

as we know that total shop of all angles quadrilateral triangle is 360 degree

so now the angle made

NOM+NPM +PMO+ONP=360 DEGREE

SO NOW,

60 DEGREE+NPM+90 DEGREE+90 DEGREE=360 DEGREE

NPM+240 DEGREE=360 DEGREE

NPM=360 DEGREE-240 DEGREE

NPM=120 DEGREE