in the adjoining figure p is a point in the interior of Angle aoB and angle aob = 40° if pm perpendicular oa and pn perpendicular OR find the measure of angle mpn
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448
heyy...here is ur ans...☺✌
we know that the sum of all angles of quadrilateral is 360°
so here in this quad.
<P + <N + <O + <M = 360
<P + 90 +90 +40 = 360
<P = 360 - 220
<P = 140°
hope it helps u....if it did plzz mark me brainliest.....thanks☺✌
we know that the sum of all angles of quadrilateral is 360°
so here in this quad.
<P + <N + <O + <M = 360
<P + 90 +90 +40 = 360
<P = 360 - 220
<P = 140°
hope it helps u....if it did plzz mark me brainliest.....thanks☺✌
panday1499999o99:
thanks for answering
Answered by
8
Answer:
140°
Step-by-step explanation:
IN ∆MPN
<MON+<ONO+<MPN+<PMO=360°
40°+90°+<MPN+90°=360°
180°+40°+MPN=360°
220°+MPN=360°
<MPN=360-220
<MPN=140°. ANS
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