Question

In the adjoining figure, P is the centre of the circle Seg PM I chord AB, If PM = 6 cm and chord AB = 16 cm then find the radius of the circle ?
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Answer 1

Step-by-step explanation:

Given- AP=34 cm is the radius of a circle with centre A.

AM=30 cm and AM⊥PQ

To find out- The length of PQ=?

Solution-

ΔAMP is a right one with AP as hypotenuse, since AM⊥PQ at M.

So, by Pythagoras theorem, we have

PM=

AP

2

−PM

2

=

34

2

−30

2

=16 cm.

So, QM=PM=16 cm

⇒QM+PM=PQ=16cm +16 cm =32cm.