Question

In the adjoining figure PA and PB are tangent to a circle with centre C. If ∠ BPC=35°,then find ∠ACP?
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Answer 1

Step-by-step explanation:

∆APC and ∆BPC are congruent by RHS

angle BPC= angle APC (cpct)

angle APC=35

angle PAC=90

angle ACP=180-(35+90)=180-125=55

Answer 2

Answer:

ur answer is already given

Step-by-step explanation:

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