in the adjoining figure, PA is a tangent to the circle with centre C. if PA = 24 CM, PB = 16 CM, find the radius of the circle
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CA is perpendicular to AP and CB is perpendicular to BP Again AC = BC = 4 (radius of the circle)Also AP = PB = (Tangents from point P)So, BPAC is a square.=> AP = PB = BC = CA = 4 cmSo, length of tangents are 4 cm each
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