In the adjoining figure, PL perpendicular to QR; LQ = LS and LR > LQ. Show that PR > PQ. (Hint. triangle PLQ congruent to triangle PLS == angle 1 = angle 3. But, angle 3 > angle 2. :. angle 1 > angle 2.]
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Hello,Buddy!!
Given:-
- PL is perpendicular to QR.
- LQ = LS
- LR > LQ
- ∆PLQ ≅ ∆PLS & Angle 1 = Angle 3
- Angle 3 > Angle 2 & Angle 1 > Angle 2
To Prove:-
- PR > PQ
Required Proof:-
In ∆PQR,
As, Angle 1 > Angle 2
Angle 1 is Large & Angle 2 is small.
WKT
- Sides Opposite to Larger Angles are Longer.
- Sides Opposite to Smaller Angles are Smaller.
So, Side Opposite is Angles 1 is PR
Side Opposite to Angle 2 is PQ
- PR > PQ
Hence, Proved.
@MrMonarque♡
Hope It Helps You ✌️ [tex][/tex]
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hope this helps!
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