In the adjoining figure, PO = QO = 3cm, angle R = 45°, angle POR = 75°, and angle Q = 60°. Prove the following :
a) ∆PQR is congruent to ∆QSO
b) PR = SQ
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Step-by-step explanation:
OP=OQ(Given)
angle PRO=angle OSQ=45° (angles opposite to equal sides)
angle POR=angleSOQ(vertically opposite angles)
IN TRIANGLE OQR and TRIANGLE QSO
OP=OQ(Given)
anglePRO=QSO
anglePOR=SOQ
a)TRIANGLE OQR is congruent to TRIANGLE QSO
b)PR=SQ(CPCT)
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