Question

) In the adjoining figure, point O is the
centre of the cirlcle, seg OM ⊥ chord AB.
If OM = 8cm, AB = 12 cm, then find OB.

Answer 1

$ab = 12cm = am + mb \\ om \: perpendicular \: ab \\ am + mb = 12cm \\ mb + mb = 12cm \\2 mb = 12 cm \\ mb = 6cm \\ (ob)^{2} = (om)^{2} + (mb) ^{2} \\ ( {ob) }^{2} = 8^{2} + {6}^{2} \\ ob ^{2} = 100 \\ ob = 10cm$