Question

In the adjoining figure pq=24 qr=26 par=degree 90 pa=6 ar=8 find QPR

Answer 1

As you have not given the figure I am assuming it.

In right triangle APR,

AP=6cm, AR=8cm and angle A=90 degrees

By Pythagoras Theorem,

PR^2=AR^2+AP^2

=PR^2=64+36=100

PR=10cm

In triangle PQR,

PQ^2+PR^2=24^2+10^2=576+100=676=26^2=QR^2

By converse of Pythagoras theorem,

Angle QPR=90 degrees

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