Question

In the adjoining figure, PQ=PR and QM=MR hence​

Answer 1

Answer:

i) in ΔPMQ & ΔPMR

PQ = PR ( given)

PM = PM ( common )

QM = RM ( given )

∴  ΔPMQ ≅ ΔPMR (by SSS)

ii) ∠PMQ = ∠PMR ( by CPCT)

iii) ∠PQM = ∠PRM ( by CPCT)

Step-by-step explanation:

HOPE U UNDESTAND IT

Answer 2

Answer:

In △PQL and △PRM

PQ=PR [ Given ]

∠PQL=∠PRM [ angles opposite to equal sides are also equal ]

QL=MR [ Given ]

∴ △PQL≅△PRM [ By SAS congruence rule ]

⇒ PL=PM [ CPCT ]