Question

In the adjoining figure, PQ=RQ and /_x=/_y.Prove that BP=AR.​

Answer 1

Step-by-step explanation:

PSR=x∠QSR + ∠PSR =180° Linear Pair∠QSR =180°-x∠REP=y∠QEP + ∠REP =180°∠QEP =180°-y=180°-x Since x=yIn ∆ QEP and ∆ QSR∠QEP = ∠QSR Proved above∠PQE=∠RQS CommonPQ=QR GivenBy AAS Congruence∆ QEP≅∆ QSRSo,PE=RS ( CPCT) ans

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