in the adjoining figure , PQ||RS then find anle Q and angle P
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Answer:
Angle P = 70°
Angle Q=90°
Explanation:
For detailed explanation refer to the image attached.
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Using the fact that OP || RS, we know that
∠RWV = 180° − 130°
1. ∠RWV = 50°
We know that,
∠PWQ = ∠RWV = 50° (Since, opposite angles of intersecting lines are equal)
Also, for line OP
∠OQP + θ = 180°
θ = 180° − ∠OPQ = 180° − 110°
2. θ = 70°
Now, we know that sum of angles of a triangle is 180°,
∠PQR + θ + ∠PWQ = 180°
∠PQR = 180° − θ − ∠PWQ = 180° − 70° − 50°
∠PQR = 180° − 120°
∠PQR = 60°
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