In the adjoining figure, PQR
is an equilateral triangle
inscribed in a circle of radius
7 cm. Find the area of the
shaded region.
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Given AB=BC=CA=6 cm
we haveO as the circumcenter
angle OBA=30
in triangle BOM
COS 30=BM/BO
√3/2=3/r
r=2√3cm
Area of shaded region =Area of circle - Area of triangle ABC
Area of shades region =Πr^2-√3/4×side ^2
Area of shaded region =(3.14)×(2√3^2)-√3/4×6^2
Area of shaded region =36.68-15.59
∴ Area of shaded region =22.126 cm sq
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