In the adjoining figure, prove that AABC = ADCB, if AC = DB and
ZA = ZD = 90°.
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In ∆ABC and ∆DCB,
/ BAC= / BDC [Each 90°]
AC=BD [Given]
BC= BC [Common]
therefore, ∆ABC=∆DCB [ By RHS Congruency]
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