In the adjoining figure, QR is a common tangent to the given circles,
which touch externally at T. Tangent at T meets QR at P. If QP = 3.8 cm,
find the length QR.
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Answer:
7.6 cm
Step-by-step explanation:
Lengths of the tangents drawn from an external point to a circle are equal.
∴ QP = PT = 3.8 cm ............ (i)
PR = PT = 3.8 cm ............ (ii)
• From equations (i) and (ii) :
QP = PR = 3.8 cm
But, QR = QP + PR
∴ QR = 3.8 + 3.8
⇒ QR = 7.6 cm
Hope it helps
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