Question

in the adjoining figure , R is the centre of the
circle. Seg RB is equal to seg BC.
Find / BAC​

Answer 1

Hi✌️✌️

If. AD = AC

1/2 AD = 1/2 AC

AP = AQ

In ∆ APM & ∆ AQM,

Ang. APM = Ang. AQM

AM = AM

AP = AQ

Hence, ∆APM is congruent to ∆AQM

So, ang. PAM = ang. QAM

Hence it is proved that, seg AB is the bisector of angle DAC.