in the adjoining figure ray PT is the bisectore of angle QPR find the value of X and perimeter of triangle PQR
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PT bisects ∠PQR,
Thus, QTPQ=RTPR
45.6=5x
x=45.6×5
x=7 cm
Perimeter = PQ + QR + PR
Perimeter = 5.6 + 5 + 4 + 7
Perimeter=21.6 cm
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