Math, asked by rajpoootsavitri, 5 hours ago

in the adjoining figure Rhombus, ABCD is a parallelogram in which , ∆BAD = 65° and ∆DBC = 70° calculate ∆CDB and ∆ADB

Answers

Answered by rehansaiyed2262007

0

Answer:

Triangle CDB = 135 degree , triangle ADB = 90 degree.

Step-by-step explanation:

thx

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