in the adjoining figure Rhombus, ABCD is a parallelogram in which , ∆BAD = 65° and ∆DBC = 70° calculate ∆CDB and ∆ADB
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1
Answer:
Step-by-step explanation:
Triangle CDB = 135 degree , triangle ADB = 90 degree.
Answered by
1
Opposite angles of parallelogram are equal.
∠DAB=∠BCD=75
o
and ∠DBC=60
o
∠BDC+∠DBC+∠BCD=180
o
∠BDC=180
o
−∠DBC−∠BCD=180
o
−75
o
−60
o
=45
o
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