In the adjoining figure,seg pq parallel to seg bc,ap:pb=3:4 if a(quadrilateral pqcb)=160 then find a(∆abc)
Answers
Answered by
0
Area of ΔABC = 196 cm² if AP:PB=3:4 , PQ || BC , A(PQCB)=160,then find A(∆ABC)
Step-by-step explanation:
Let say Area of ∆ABC = A
PQ ║ BC
=> ΔAPQ ≈ ΔABC
AP/AB = AP/(AP + PB) = 3/(3 + 4) = 3/7
Area of ΔAPQ / Area of ΔABC = (3/7)²
=> Area of ΔAPQ / Area of ΔABC = 9/49
A(PQCB)= Area of ΔABC - Area of ΔAPQ
=> 160 = Area of ΔABC - (9/49)Area of ΔABC
=> 160 = (40/49)Area of ΔABC
=> Area of ΔABC = 196 cm²
Learn more:
In the adjoining figure seg pq || seg bc, ap : pb = 3: 4 if a(pqcb) = 160 ...
https://brainly.in/question/14787883
The area of a triangle ABC is 10.8 cm2.if CP=PB and 2AQ= QB the ...
brainly.in/question/8990985
AP is perpendicular to BC . PC is greater than PB .PQ is equal to PB ...
brainly.in/question/12109623
Similar questions