Math, asked by ruchitakahane, 10 months ago

in the adjoining figure,seg PS perpendicular to segRQ , seg QT perpendicular to segPR.
if RQ=6 and PS=6 and PR= 12 and then find QT...
pls answer fast....​

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Answered by GMS04
1

Answer:

RQ = 6

RT = PR/2

= 6

T = 90⁰

ASP = 6 + 6 + 90⁰ = QT

= 12 / 90⁰ QT

= 7.5

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Answered by shindedropadi
0

Answer:

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