Math, asked by shlokgupta25jan2015, 8 months ago

in the adjoining figure, show that EI is the bisector of <KET and <KIT....... get 100 points for free by answering the correct answer !!!​

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Answered by avitaylor101
3

Step-by-step explanation:

In triangle ABC, ∠B = 90°

seg BD ⊥ Hypotenuse AC

∴ ΔABC ≈ ΔADB

#(13 * 5 = 65)

#Refer the figure for better understanding.

Take the length of AC = 13 c.m and and mark point D at 5 c.m.

∴ AB/AD = AC/AB

∴ AB² = AD × AC

∴ AB² = 13 × 5

∴ AB² = 65

∴ AB = √65

So, Length of the seg AB is √65.

Answered by itzcrazykamini12
2

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