Question

in the adjoining figure ,the diagonals AC and BD of a quadrilateral ABCD intersect at O , at right angles.prove that ab^2+cd^2=ad^2+bc^2​

Answer 1

I hope I helped!! I took one side of the equation first and wrote it in the form of sum of squares of sides from the figure using Pythagoras Theorem as they intersected at right angles. I did the same one the rhs and it turned out to be the same soo hence proved.

Answer 2

Answer:

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Step-by-step explanation:

take out all triangles sides and using pythageourous theroum and add both equation