In the adjoining figure, the point D divides
the side BC of A ABC in the ratio m:n.
Prove that ar(triangle. ABD): ar(triangle ADC)=m:n
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Answer:
r(Δ ABD) = ½*B * H
= ½ * BD * AE
ar(Δ ADC) = ½ * B * H
= ½ * CD * AE
Now, their ratio :
½*BD*AE/1/2*CD*AE = BD/CD
Therefore BD/CD = BD : CD i.e m:n
Hence proved.
Step-by-step explanation:
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