In the adjoining figure, there is a circle with O as its centre
Radius OP = 10 cm and OR perpendicular on chord PQ is 6
cm. PQ will be equal to
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Answer:
PR^2=OP^2-OR^2(using Pythagoras theorem)
PR^2=10^2-6^2
=100-36=64
PR=8 cm
PQ=2*8=16cm
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