Question

in the adjoining figure triangle ABC is right angled at A, BC is equal to 7.5 cm and a b is equal to 4.5 CM if the area of quadrilateral ABCD is 30 cm square and DL is the altitude of triangle D AC calculate the length DL ​

Answer 1

Answer:

Therefore, DL will be equal to 11 cm

Answer 2

Step-by-step explanation:

Area of Quadrilateral 30 cm square

Area of triangle ABC =?

Using Pythagoras theorem

H ^2=P^2+B ^2

Ac^2=BC ^2-AB ^2

AC^2=7.5 ^2-4.5^2

AC ^2=56.25 -20.25

AC =6cm

Area of triangle ABC =1/2 *6*4.5

=13.5 cm

Area of triangle DAC =Area of Quadrilateral ABCD -Area of triangle ABC

30-13.5

16.5 cm^2

Area of triangle DAC =16.5cm^2

DL =?

Area of triangle DAC =16.5cm^2

1/2 *AC*DL =16.5 cm ^2

1/2*6*DL=16.5 cm ^2

DL = 5.5 cm