Question

In the adjoining figure, triangle ABC is right-angled at A. Q and R are points on line BC and P is a point such that QP II AC and RP IIAB. Find angle P.

Answer 1

Angle P = 90°

Step-by-step explanation:

See the attached diagram.

Here, Angle ∠ BAC is 90° and Q and R are two points on the line BC.

And given that P is a point such that QP ║ AC and RP ║ AB.

Therefore, the angle between lines AC and AB i.e. ∠ BAC = 90° and hence, the angle between line QP and RP i.e. ∠ QPR = 90°.

So, angle P = 90° (Answer)