in the adjoining figure triangle pqr is a right angled at Q in which QR is equal to 6 CM and PQ is equal to 7 cm find the area of triangle qsr given that PS is parallel to QR
Answers
Answer:
(1+x)
dx
dy
−xy=1−x
dx
dy
+(
1+x
−x
)y=
1+x
1−x
∫pdx=∫
1+x
−x
=−∫
1+x
1+x−1
dx
=−∫1−
1+x
1
dx
=−x+log∣1+x∣dx
I.Fe
∫pdx
=e
log(1+x)−x
=
e
x
1+x
4.5y.
e
x
1+x
=∫
e
x
1−x
y
e
x
(1+x)
=∫e
−x
(1−x)
y(1+x)=e
x
c
−x
(+x)
y(1+x)=x
Step-by-step explanation:
=》}=》 Area of the wall including door = length × breadth
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}}
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now,
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now,
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now,
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now,
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now,
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now, Area of wall excluding door = Area of wall including door - Area of rectangular door
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now, Area of wall excluding door = Area of wall including door - Area of rectangular door\red {=》}=》 16.2 m² - 2 m²
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now, Area of wall excluding door = Area of wall including door - Area of rectangular door\red {=》}=》 16.2 m² - 2 m²\red {=》}=》 14.2
=》}=》 Area of the wall including door = length × breadth\red {=》}=》 4.5 m. × 3.6 m. = 16.2 m²\red {=》}=》 Area of rectangular door = length × breadth\red {=》}=》 2m. × 1m. = 2 m²\huge{\underline{\underline{Now,}}} Now, Area of wall excluding door = Area of wall including door - Area of rectangular door\red {=》}=》 16.2 m² - 2 m²\red {=》}=》 14.2.Prove that x⁵-5x³+5x²-1=0 has three equal roots and find this root.
The rate of white washing of 1 m² the wall = 20