Question

in the adjoining figure, triangle PQR is an equilateral triangle,seg PM is a perpendicular to seg QR. Then prove that PQ^2=4QM^2​

Answer 1

Answer:

• $PQ^{2} = 4(QM)^{2}$     [Proved]

Step-by-step explanation:

Since ΔPQR is an equilateral triangle

So, PQ = QR = PR

Since PM is Perpendicular to segment QR of the equilateral ΔPQR

So, PM is the median of QR.

Therefore, QR  =  2QM

               ⇒ PQ = 2QM           [ Since PQ= QR]

             ⇒ $PQ^{2} = (2QM)^{2}$      [Squaring both side]

           ⇒ $PQ^{2} = 4 (QM)^{2}$       [Proved]

Answer 2

Answer:

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Step-by-step explanation:

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