in the adjoining figure x:y:z =5:4:6.if aob is a straight line find the value of xyz
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Given : AOB is a straight line.
Let x = 5a , y = 4a , z = 6a
∠AOE + ∠EOD + ∠BOD = 180° [By linear pair axiom ]
x + y + z = 180°
5a + 4a + 6a = 180°
15a = 180°
a = 180/15
a = 12
∠AOE = x = 5a = 5 × 12 = 60°
∠EOD = y = 4a = 4 × 12 = 48°
∠BOD = z = 6a = 6 × 12 = 72°
Hence, the value of x = 60° , y = 48° & z = 72°
HOPE THIS WILL HELP YOU...
Let x = 5a , y = 4a , z = 6a
∠AOE + ∠EOD + ∠BOD = 180° [By linear pair axiom ]
x + y + z = 180°
5a + 4a + 6a = 180°
15a = 180°
a = 180/15
a = 12
∠AOE = x = 5a = 5 × 12 = 60°
∠EOD = y = 4a = 4 × 12 = 48°
∠BOD = z = 6a = 6 × 12 = 72°
Hence, the value of x = 60° , y = 48° & z = 72°
HOPE THIS WILL HELP YOU...
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Answer:let the x:y:z be 5x 4x 6x
Step-by-step explanation:5x,4x,6x =180 (straight line)
x=180/15 (5+4+6)
x=12
5x *12 =60
6x*12= 48
6x*12=72
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