In the adjoining figure, XY = XZ. YQ and ZP are the bisectors
of ZXYZ and ZXZY respectively. Prove that YQ = ZP.
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In given figure ∠X=62
∘
,∠XYZ=54
∘
. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of ΔXYZ . find ∠OZY and ∠YOZ .
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As the sum of all interior angles of a triangle is 180º, therefore, for ΔXYZ,
∠X + ∠XYZ + ∠XZY = 180º
62º + 54º + ∠XZY = 180º
∠XZY = 180º − 116º
∠XZY = 64º
∠OZY = 32º (OZ is the angle bisector of ∠XZY)
Similarly, ∠OYZ == 27º
Using angle sum property for ΔOYZ, we obtain
∠OYZ + ∠YOZ + ∠OZY = 180º
27º + ∠YOZ + 32º = 180º
∠YOZ = 180º − 59º
∠YOZ = 121º
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