Question

In the adjoining figure, ZB = 90°, ZBAC =0", BC = CD = 4 cm ang
D
AD = 10 cm. Find (i) sin 0 and (ii) cos 0.
2po2+36 m2​

Answer 1

Answer:

(i) sinθ=2/√13

(ii)cosθ3/√13

Step-by-step explanation:=

in ΔABD

AB²=AD²-BD²

=10²-8²=100-64=36

AB=√36=6 CM

In ΔABC

AC²=AB²+BC²

=6²+4²=36+16=36+16=52

AC=√52=2√13

Now in ΔABC(i) sinθ=BC/AC=4/2√13=2/√13

(ii)cosθ=AB/AC=6/2√13=3/√13

∠

Δ