In the adjoining figure, ZPOQ is a straight line. If ZPOR=45° and ZSOQ=52°, find the measure of ZROS.
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Answer:
lnΔPRT
∠RPT+∠PRT+∠RTP=180
∘
(angle sum property of a triangle)
⇒95
∘
+40
∘
+∠RTP=180
∘
⇒135
∘
+∠RTP=180
∘
⇒∠RTP=180
∘
−135
∘
=45
∘
Now ∠RTP=∠STQ=45
∘
(vertically opposite angles)
lnΔSTQ
∠STQ+∠TSQ+∠SQT=180
∘
(angle sum property of a triangle)
⇒45
∘
+75
∘
+∠SQT=180
∘
⇒∠SQT=180
∘
−(45
∘
+75
∘
)
=180
∘
−120
∘
=60
∘
Hence, ∠SQT=60
∘
Step-by-step explanation:
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