Question

In the adjoining figure, ZX = 62°, ZXYZ = 54º. If
YO and ZO are the bisectors of ZXYZ and ZXZY
respectively of AXYZ, then find ZOZY and ZYOZ​

Answer 1

hey dude meet your answer :

Given, ∠X=62 ,∠XYZ=54

Given, ∠X=62 ,∠XYZ=54

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)⇒62 +54 +∠XZY=180

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)⇒62 +54 +∠XZY=180 116 +∠XZY=180

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)⇒62 +54 +∠XZY=180 116 +∠XZY=180 ∠XZY=64

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)⇒62 +54 +∠XZY=180 116 +∠XZY=180 ∠XZY=64

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)⇒62 +54 +∠XZY=180 116 +∠XZY=180 ∠XZY=64 Now, ∠OZY= 21

Given, ∠X=62 ,∠XYZ=54 YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively.According to the question∠X+∠XYZ+∠XZY=180 (Sum of the interior angles of the triangle.)⇒62 +54 +∠XZY=180 116 +∠XZY=180 ∠XZY=64 Now, ∠OZY= 21 ∠XZY(ZO is the bisector.)

⇒∠OZY=32

⇒∠OZY=32

⇒∠OZY=32 Also ∠OYZ= 21

⇒∠OZY=32 Also ∠OYZ= 21∠XYZ (YO is the bisector.)

⇒∠OZY=32 Also ∠OYZ= 21∠XYZ (YO is the bisector.)⇒∠OYZ=27°

⇒∠OZY=32 Also ∠OYZ= 21∠XYZ (YO is the bisector.)⇒∠OYZ=27°Now, ∠OZY+∠OYZ+∠O=180

⇒∠OZY=32 Also ∠OYZ= 21∠XYZ (YO is the bisector.)⇒∠OYZ=27°Now, ∠OZY+∠OYZ+∠O=180 (Sum of the interior angles of the triangle.)

⇒∠OZY=32 Also ∠OYZ= 21∠XYZ (YO is the bisector.)⇒∠OYZ=27°Now, ∠OZY+∠OYZ+∠O=180 (Sum of the interior angles of the triangle.)⇒32 +27 +∠YOZ=180

⇒59 +∠YOZ=180

⇒59 +∠YOZ=180

⇒59 +∠YOZ=180 ⇒∠YOZ=121

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