Question

in the adjoining figureQR=RS, QS=QT
find x and y

Answer 1

Solution: Since, QR=RS
Therefore, ∆QRS is an isosceles triangle.
So, Angle y°=angleRSQ ...1

By the sum property of angle of∆s.
50°+y°+angle RSQ=180°
From 1, 50°+y°+y°=180°
or, 2y= 180°-50°
or,. y= 65°
Now , by linear pair of angle
angle RSQ+angle QST=180°
or, 65°+ angle QST=180°
or,. angle QST= 180°-65°
or,. angle QST= 15° ...2
Since, QS=QT
Therefore, angle QST=angle QTS
From 2, angle QTS=15°
So, x°= 15°