Question

In the adjoining figures
arc AXC and arc AYC are
drawn with radius 8 cm
and centres as point B and
point D respectively. Find
the area of shaded region
if (ABCD is a square with
side 8 cm
(4 marks)
​

Answer 1

Answer:36.48

1.Area of quad circle a1=3.14*8²/4

2.Area of triangle a2=1/2(8*8)

3.So area of shaded regions =2(a1-a2)

4.I.e. 36.48

Answer 2

Given:

Side of square ABCD,

= 8 cm

Radius of adjoining figures,

= 8 cm

To Find:

The Area of shaded region = ?

Solution:

As we know,

The Area of quad circle,

⇒  $A1=\frac{1}{4}\pi r^2$

On putting the values, we get

⇒  $A1=\frac{1}{4}\times 3.14\times (8)^2$

⇒       $=50.24$

The Area of a triangle,

⇒  $A2=\frac{h\times b}{2}$

⇒        $=\frac{8\times 8}{2}$

⇒        $=32$

Now,

The Area of shaded region,

= $2(A1-A2)$

= $2(50.24-32)$

= $2\times 18.24$

= $36.48$

So that the shaded region's area will be "36.48 cm²".