in the adjoining parallelogram AF and CE are the attitudes correspondinding to sides BC and AB respectively. if the area of the parallelogram is 885.60sq cm, AB=36cm andBC=48cm, find the length of CE and AF.
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Let the area from the triangle formed from side AB=area formed from triangle formed from side AD.
Area formed from AB's triangle: (1/2)*6 cm*10 cm (Area of triangle is one-half bas times height).
Area=30 square cm
Solve for side AD
30=(1/2)*8 cm*AD
30=4*AD
30/4=AD or AD=7.5 cm
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