in the adjoining quadrilateral ABCD, AO and BO are the bisectors of angle A and angle B respectively. prove that angle AOB =1/2(angle C + angle D)
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Answer:
ABCD is a quadrilateral
To prove : ∠AOB=
2
1
(∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
2
1
(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5=
2
1
(∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+
2
1
(∠C+∠D)
∠AOB=
2
1
(∠C+∠D)
Hence,Proved.
Step-by-step explanation:
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