Question

in the Adjoining quadrilateral ABCD,diagonal AC=48cm DP and BQ are perpendiculars To AC. DP=17.5Cm and BQ=12cm Find the area of quadrilateral ABCD.

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Answer 1

REQUIRED ANSWER:

• Area of quadrilateral is 588cm².

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EXPLAINATION:

Here according to the given information diagram can be made as given in the attachment.

From the figure we can see that the quadrilateral is made up of 2 triangles whose base and altitudes are given. We can find the area of whole quadrilateral by finding the sum of areas of both triangles.

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$\bf{So\: let's\: start!}$

GIVEN:

• Height of triangle ADC=17.5cm
• Height of triangle ABC=12cm
• Common base of both triangles=48cm

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TO FIND:

• Area of quadrilateral

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SOLUTION:

★ Area of triangle ADC=½×base×height

=> ½×48cm×17.5xm

=>420cm²

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★ Area of triangle ABC=½×base×height

=> ½×48cm×12cm

=> 168cm²

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Area of quadrilateral will be sum of areas of both triangles.

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Area of ABCD=Ar.ABC+Ar.ADC

=> 420cm²+168cm²

=> 588cm²

Hence the required area is 588cm².

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Answer 2

Answer:

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