Question

In the ambiguous case of the solution of ∆s, prove that the circumcircles of the two ∆s are of same size.​

Answer 1

Given :

• In the ambiguous case of the solution of triangle

To prove :

• that the circumcircles of the two triangles are of same size.

Solution :

Let us say b, c and angle B are given in the

ambiguous case. Both the triangles will have b and its opposite angle B

so b/sin B = 2R

will be given for both the triangles. So their circumradii and there by their sizes will be same.

Extra information :

sum of all angles of a triangles 180°

A triangle has three sides, three vertices, and three angles.

The area of a triangle is equal to half of the product of its base and height.

Answer 2

Answer:

$\huge\boxed{\fcolorbox{red}{blue}{Answer}}$

${\huge{\red{\underline{\underline{Given:}}}}}$

• In the ambiguous case of the solution of triangles.

${\huge{\red{\underline{\underline{To \ prove:}}}}}$

• That the circumcircles of the two triangles are of same size.

${\huge{\red{\underline{\underline{Solution:}}}}}$

Let us say b,c and angle B are given in the ambiguous case.Both the triangles will have b and its opposite angle B.

so,b/sin B=2R

will be given for both the triangles.So their circum radius and there by thier sizes will be same..

$\boxed{\fcolorbox{red}{blue}{Proved}}$