Question

In the angle ABC, AD divides angle BAC in the ratio 1:3 AD =DB. Determine the value of angle ACB. ​

Answer 1

Answer:

AD divides ∠ BAC in the ratio 1 : 3.

So, let ∠BAD=y and ∠DAC=3y

Now,

y+3y+108=180

4y=72

y=18

Now, since AD = BD, therefore,

∠BAD=∠ABD=y=18

∠ADC=2y=36

Therefore, in △ADC,

x+36+54=180

x=90

o

Answer 2

Answer:

$1236555547789 \times 12547896322154566987622222222$