Question

In the ap 598,621....920 theNth term is 920 what is the value of n plz tell the ans

Answer 1

Answer:

Here,

$a = 598 \\ d = 23 \\ {n}^{th} \: term = 920 \\ \\ {n}^{th} = a + d(n - 1) \\ 920 = a + d(n - 1) \\ 920 = 598 + 23(n - 1) \\ 920 = 598 + 23n - 23 \\ 920 + 23 - 598 = 23n \\ 345 = 23n \\ 15 = n$

Hope this helps.

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