Question

in the ap first value is -4 last term is 29 and the sum of all its terms is 150 find it's common difference
Ap question​

Answer 1

Answer:

The answer will be 3.

Step-by-step explanation:

We have given;

a or first term = -4;

al or last term= 29;

S or Sum = 150;

S = n/2 × ( a + al) here, n = no. of terms

Thus, 150 = n/2 × (-4 + 29)

150 = n/2 × 25

6 = n/2;

n = 12.

Now, al = a + d(n-1) where, d = common difference.

29 = -4 + d( 12-1 );

33 = d × 11

d = 3.

Thus, common difference in this AP will be 3.

That's all.

Answer 2

Answer:

a= -4

l=29

sum of term = 150

Sn=n/2(a+l)

150=n/2(-4+29)

300=25n

n=12

A12 =29(last term of Ap whose sum is 150)

a+11d=29

-4+11d=29

11d=29+4

11d=33

d=3