Question

In the aqueous solution of sulphuric acid the mole fraction of water is 0.85. The molality of the solution is-

Answer 1

Answer:9.8 molal

Explanation:

Answer 2

mol fraction of water in solution  = 0.85

So mol of acid = 1-0.85 = 0.15

Now

m=  

nw×molecularwtofwater

1000×molofacid

​  

 

m=  

0.85×18

1000×0.15

​  

 

=9.8mol/kg