Question

In the arithmetic progressions 2,5, 8, ... upto 50 terms, and 3, 5, 7, 9, ... upto 60
Germs, find how many terms are identical.


kindly help me as soon as possible ​

Answer 1

Answer:

For the first A.P

A

n

=2+(x−1)3=3x−1 when 0<x<51

For second A.P,

B

n

=3+(y−1)

2

=2y+1 when 0<y<61

where x and y are inyegers.

when x is an even no., it satisfies this condition.

Hence

x=2, y=2

x=4, y=5

x=6, y=8

.

.

.

.

.

x=40, y=59

Hence, 20 terms are identical.

Answer 2

Answer:

20

Step-by-step explanation:

For the first A.P

An=2+(x−1)3=3x−1 when 0<x<51

For second A.P,

Bn=3+(y−1)2=2y+1 when 0<y<61

where x and y are inyegers.

when x is an even no., it satisfies this condition.

Hence 

x=2,  y=2

x=4, y=5

x=6, y=8

.

.

.

.

.

x=40, y=59

Hence, 20 terms are identical.