Question

. In the arrangement as shown below m, = 1 kg, m, = 2 kg. Pulleys are massless and strings are light. For
what value of M the mass m, moves with constant velocity? (Neglect Friction)
M
m
m
(1) 4 kg
(2) 8 kg​

Answer 1

Answer:

Now, according to question, m1​ moves with

constant velocity

⇒a1−a=0⇒a1=a​       ....(i)

From figure above ,

T−m1​g=0⇒T=m1​g=1×9.8

⇒T=9.8N​       .....(ii)

2T=Ma

⇒Ma=19.6​ (from (ii))     ...... (iii)

m2​g−T=a+a1=29  (from (i))

⇒2a=2×9.8−9.8

⇒a=29.8​=4.9m/s2​

putting in (iii)

M=4.919.6​

⇒M=4kg