In the arrangement shown, all strings are light and inextensible , pulleys light and smooth. All surfaces are smooth the block A moves on smooth horizontal surface towards left at a =12m/s² the block B always remain in horizontal horizontal position
Answers
Answer:
From Newton’s law:
F=
dt
dp
......(1) where, dp is the change in momentum caused after collision and dt is the time between two successive collisions.
It is given that collision is elastic thus the bead, after striking the next bead will impart velocity v to the next bead and itself come to rest.
Since the bead is reversing its direction. So the change in momentum is dp=2mv. It is assumed that 10r(L−10r) and back. Total length is 2(L−10r)
So,
dt=
v
2(L−10r)
Put this in equation (1)
F=
v
2(L−10r)
2mv
F=
(L−10r)
mv
2
Answer:
From Newton’s law:
F=
dt
dp
......(1) where, dp is the change in momentum caused after collision and dt is the time between two successive collisions.
It is given that collision is elastic thus the bead, after striking the next bead will impart velocity v to the next bead and itself come to rest.
Since the bead is reversing its direction. So the change in momentum is dp=2mv. It is assumed that 10r(L−10r) and back. Total length is 2(L−10r)
So,
dt=
v
2(L−10r)
Put this in equation (1)
F=
v
2(L−10r)
2mv
F=
(L−10r)
mv
2